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標題:
中3 數學..thx!!
發問:
(2x^2y)^3/x^10y 6^2x-3=36^x+1 4^2x=1/16 5^x+1-5^x-100=0 pa-pb-qa+qb 18z^2-12z+2 3x^4+6x^2+3 thx!!
(1) (2x^2y)^3/x^10y = 8y^2 / x^4 (2) 6^(2x-3) = 36^(x+1) 6^(2x-3) = 6^2(x+1) compare the index 2x-3 = 2(x+1) Contraction (please check your question again) (3) 4^2x = 1/16 2^4x = 2^(-4) compare the index 4x = -4 x = -1 (4) 5^(x+1) - 5^x -100 = 0 5(5^x) - 5^x = 100 4(5^x) = 100 5^x = 25 5^x = 5^2 x = 2 (5) pa-pb - qa+qb = p(a-b) -q(a-b) = (p-q)(a-b) (6) 18z^2 - 12z + 2 =2(9z^2 - 6z + 1) =2 (3x - 1)^2 (7) 3x^4 +6x^2 + 3 =3(x^4+2x^2 +1) =3(x^2+1)^2
其他解答:
解方程同因式分解？!
中3 數學..thx!!
發問:
(2x^2y)^3/x^10y 6^2x-3=36^x+1 4^2x=1/16 5^x+1-5^x-100=0 pa-pb-qa+qb 18z^2-12z+2 3x^4+6x^2+3 thx!!
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最佳解答:(1) (2x^2y)^3/x^10y = 8y^2 / x^4 (2) 6^(2x-3) = 36^(x+1) 6^(2x-3) = 6^2(x+1) compare the index 2x-3 = 2(x+1) Contraction (please check your question again) (3) 4^2x = 1/16 2^4x = 2^(-4) compare the index 4x = -4 x = -1 (4) 5^(x+1) - 5^x -100 = 0 5(5^x) - 5^x = 100 4(5^x) = 100 5^x = 25 5^x = 5^2 x = 2 (5) pa-pb - qa+qb = p(a-b) -q(a-b) = (p-q)(a-b) (6) 18z^2 - 12z + 2 =2(9z^2 - 6z + 1) =2 (3x - 1)^2 (7) 3x^4 +6x^2 + 3 =3(x^4+2x^2 +1) =3(x^2+1)^2
其他解答:
解方程同因式分解？!
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