close
標題:
發問:
我想問下以下幾題ge數學題，亦請回答ge人show 埋個step，詳細1d ...麻煩哂！1)The general term of a sequence is 7-3n. List out the five terms of that sequence.2)Shui Wah is the tutor of Chi Keung. The tutorial fee is $120 per hour. Each time, Shui Wah has $10 travel allowance. Chi Keung has 4 tutorial lessons in July. The total fee... 顯示更多 我想問下以下幾題ge數學題，亦請回答ge人show 埋個step，詳細1d ...麻煩哂！ 1) The general term of a sequence is 7-3n. List out the five terms of that sequence. 2) Shui Wah is the tutor of Chi Keung. The tutorial fee is $120 per hour. Each time, Shui Wah has $10 travel allowance. Chi Keung has 4 tutorial lessons in July. The total fee is $880. How many hours does Chi Keung have? 3) Solve the equation of the following questions. a) 1/3y+2y=14 b) 1/3(2m6+1)-1=1-m 4) A, B, C have a total of 60kg rice. If A has one third of the rive of B and Bhas 5 times as much as C. Find the amount of rice each person has. 5) In September, there are 37 students in F.5C. In October, the number of students in F.5C became 39. Find the percentage increase. (correct the answer to 3 significant figures) thx!
最佳解答:
1) The general term of a sequence is 7-3n. List out the five terms of that sequence. Answer: Sequence= 7-3n If n=1, then 7-3n= 4 If n=2, then 7-3n= 1 If n=3, then 7-3n= -2 If n=4, then 7-3n= -5 If n=5, then 7-3n= -8 Therefore, fove terms of sequence= 4,1,-2,-5,-8. 2) Shui Wah is the tutor of Chi Keung. The tutorial fee is $120 per hour. Each time, Shui Wah has $10 travel allowance. Chi Keung has 4 tutorial lessons in July. The total fee is $880. How many hours does Chi Keung have? Answer: Tutorial fee= $120 per hour Allowance= $10 No. of lessons in a month= 4 Therefore, total allowance= 4*$10= $40 Let the no. of hours be x. Therefore, 120x*4+10*4= 880 480x+40= 880 480x= 840 x= 1.75 Therefore, Chi Keung has 1.75 hours (1 hour and 45 minutes) 3) Solve the equation of the following questions. a) 1/3y+2y=14 y (1/3+2)= 14 y= 14/(1/3+2) y= 6 b) 1/3(2m6+1)-1=1-m ( I believe "2m6" means "2m*6, right?) 1/3 (12m+1)= 1-m+1 12m+1= (2-m)*3 12m+3m+1-1= 6-3m+3m-1 15m= 5 m= 1/3 4) A, B, C have a total of 60kg rice. If A has one third of the rice of B and B has 5 times as much as C. Find the amount of rice each person has. Answer: Let amount of rice A have= a (kg) Then amount of rice B have= 3a (kg) Then amount of rice C have= 3/5a (kg) Therefore, a+3a+3/5a= 60 4.6a= 60 a= 13 and 1/23 (kg) Then, 3a= 39 and 3/23 (kg) Then, 3/5a= 7 and 19/23 (kg) Therefore, A have 13 and 1/23 (kg) of rice, B have 39 and 3/23 (kg) of rice and C have 7 and 19/23 (kg) of rice. 5) In September, there are 37 students in F.5C. In October, the number of students in F.5C became 39. Find the percentage increase. (correct the answer to 3 significant figures) Answer: Percentage increase= (New amount of people-Original amount of people)/ Original amount of people*100% Therefore, Percentage increase= (39-37)/37*100%= 5.41% (corr. to 3 sign. fig.)
其他解答:
此文章來自奇摩知識+如有不便請留言告知
數學難題解答....急~~幫忙幫忙~~入~~~20點.~發問:
我想問下以下幾題ge數學題，亦請回答ge人show 埋個step，詳細1d ...麻煩哂！1)The general term of a sequence is 7-3n. List out the five terms of that sequence.2)Shui Wah is the tutor of Chi Keung. The tutorial fee is $120 per hour. Each time, Shui Wah has $10 travel allowance. Chi Keung has 4 tutorial lessons in July. The total fee... 顯示更多 我想問下以下幾題ge數學題，亦請回答ge人show 埋個step，詳細1d ...麻煩哂！ 1) The general term of a sequence is 7-3n. List out the five terms of that sequence. 2) Shui Wah is the tutor of Chi Keung. The tutorial fee is $120 per hour. Each time, Shui Wah has $10 travel allowance. Chi Keung has 4 tutorial lessons in July. The total fee is $880. How many hours does Chi Keung have? 3) Solve the equation of the following questions. a) 1/3y+2y=14 b) 1/3(2m6+1)-1=1-m 4) A, B, C have a total of 60kg rice. If A has one third of the rive of B and Bhas 5 times as much as C. Find the amount of rice each person has. 5) In September, there are 37 students in F.5C. In October, the number of students in F.5C became 39. Find the percentage increase. (correct the answer to 3 significant figures) thx!
最佳解答:
1) The general term of a sequence is 7-3n. List out the five terms of that sequence. Answer: Sequence= 7-3n If n=1, then 7-3n= 4 If n=2, then 7-3n= 1 If n=3, then 7-3n= -2 If n=4, then 7-3n= -5 If n=5, then 7-3n= -8 Therefore, fove terms of sequence= 4,1,-2,-5,-8. 2) Shui Wah is the tutor of Chi Keung. The tutorial fee is $120 per hour. Each time, Shui Wah has $10 travel allowance. Chi Keung has 4 tutorial lessons in July. The total fee is $880. How many hours does Chi Keung have? Answer: Tutorial fee= $120 per hour Allowance= $10 No. of lessons in a month= 4 Therefore, total allowance= 4*$10= $40 Let the no. of hours be x. Therefore, 120x*4+10*4= 880 480x+40= 880 480x= 840 x= 1.75 Therefore, Chi Keung has 1.75 hours (1 hour and 45 minutes) 3) Solve the equation of the following questions. a) 1/3y+2y=14 y (1/3+2)= 14 y= 14/(1/3+2) y= 6 b) 1/3(2m6+1)-1=1-m ( I believe "2m6" means "2m*6, right?) 1/3 (12m+1)= 1-m+1 12m+1= (2-m)*3 12m+3m+1-1= 6-3m+3m-1 15m= 5 m= 1/3 4) A, B, C have a total of 60kg rice. If A has one third of the rice of B and B has 5 times as much as C. Find the amount of rice each person has. Answer: Let amount of rice A have= a (kg) Then amount of rice B have= 3a (kg) Then amount of rice C have= 3/5a (kg) Therefore, a+3a+3/5a= 60 4.6a= 60 a= 13 and 1/23 (kg) Then, 3a= 39 and 3/23 (kg) Then, 3/5a= 7 and 19/23 (kg) Therefore, A have 13 and 1/23 (kg) of rice, B have 39 and 3/23 (kg) of rice and C have 7 and 19/23 (kg) of rice. 5) In September, there are 37 students in F.5C. In October, the number of students in F.5C became 39. Find the percentage increase. (correct the answer to 3 significant figures) Answer: Percentage increase= (New amount of people-Original amount of people)/ Original amount of people*100% Therefore, Percentage increase= (39-37)/37*100%= 5.41% (corr. to 3 sign. fig.)
其他解答:
文章標籤
全站熱搜
留言列表
